Chemistry HELP

Complete combustion of 3.30 g of a hydrocarbon produced 10.2 g of CO2 and 4.68 g of H2O. What is the empirical formula for the hydrocarbon?

I did the calculation and the ratio comes out to
C: 1 H: 2.24

So I thought the answer is CH2 but apparently its wrong. Anyone help..

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  1. With 1:2.24 you can't round to 1:2.
    Multiply by a whole number until you get two whole numbers (or at least to close whole numbers).
    1:2.24
    2:4.48
    3:6.72
    4:8.96 which I would round to 4:9
    for the formula C4H9. Having done that I don't know what to do except look at your data for as far as know there is no C4H9. But I would key in C4H9; the person in charge of making up these problems may not have worked it through.

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