chemistry

Calculate the pH of .100 of a buffer solution that is .25 M in HF and .50 M in NaF. What is the change in pH on addition of the following?

A. .002 mol of HNO3
B. >004 mol of KOH

I calculated the correct pH of the solution but am having trouble calculating A & B.

Thanks,
Ivy

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  1. What's that 0.100? 0.100 L?
    millimols HF = mL x M = 100 x 0.25 = 25.0
    millimols NaF = 100 x 0.500 = 50,0
    Add 0.002 = 2 millomils HNO3

    .........F^- + H^+ ==> HF
    I.......50.0...0......25.0
    add.............2..........
    C........-2....-2......+2
    E........48.....0.....27

    Then plug the E line values into the HH equation and solve for pH.

    Addition of NaOH is done the same way but use the reverse chemical equation since this is a base added.

    .........HF + OH^- ==> F^- + H2O

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