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What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.

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Max

  1. V^2 = Vo^2 + 2g*h = 0 at max. ht.
    40^2 - 19.6*h = 0
    19.6h = 1600
    h = 81.6 m.

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    Henry

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