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a 0.76 mol sample of pcl5 is placed in a 500 ml reaction vessel. what is the concentration of pcl5 when the reaction

pcl5(g) ⇀↽ pcl3(g) + cl2(g)

has reached equilibrium at 250◦c (when kc = 1.8)

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asked by amanda
  1. kc= [x)(x)/(2*.76-x)= 1.8

    x^2=1.8(1.52-x)
    solve that quadratic for x

    x^2+1.8x-2.74=0

    x= (-1.8+-sqrt(3.24+10.96) )/2

    x= -.9+- 3.77/2= ..985 moles/liter

    or conce of Pcl5 is 2*.76-.985

    check my math.

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