# Calculus

Find the distance between the given parallel planes.
4z = 4y − 4x, 6z = 3 − 6x + 6y

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1. pick a point in plane #1, say (2,3,1)

Now just use the distance formula to get the distance to

6x-6y+6z=3
or, equivalently,
2x-2y+2z-1 = 0

d = |2*2-2*3+2*1-1|/√(2^2+2^2+1^2) = 1/√5

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posted by Steve

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