# Math

A rectangular box has a length of 12 inches and a width 4 inches. The length of the three-dimensional diagonal of the box is 14 inches. What is the height of the box?

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1. let the height be h
h^2 + 12^2 + 4^2 = 14^2
h^2 + 144 + 16 = 196
h^2= 36
h = √36 = 6

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posted by Reiny

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