Ok this is what i got for the grams part now....
Total mass is 20.14 + 51.64 + 11.34 + 15.06 = 98.18
%H2O = (20.14/98.18)*100 = 20.51%
%C2O4 = (51.64/98.18)*100 = 52.60%
% Fe 3+ = (11.34/98.15) * 100= 11.55%
% K + = (15.06/98.15) * 100 = 15.43 %
20.51 g H2O, 52.60 g C2O4 11.55 g Fe 3+, 15.43 g K+
you said redo the mols and percent... can you give me an example of how please
Answered below.
ok i did all the mols of those numbers and came out with
H2O = (20.51/18.051)=1.136
C2O4 = (52.60/88.016)=.5976
Fe 3+ = (11.55/55.845)= .2068
K + = (15.34/39.098)=.3923
Ive gotten that far... now im a little confused on how you do the rest of the question because they don't come out to whole numbers can you show me an example please
Divide all the numbers by the smallest number, in this case that is 0.2068. Then round to the nearest whole number. If you have one that will round to 1/2, then multiply all by 2 to get rid of the 1/2. If you still don't get it, post your values for the division along with what the mols are for; i.e.,
H2O = 5.5 etc.
These numbers aren't coming out with anything I recognize; perhaps the teacher just made up a problem.
1.136/.2068=5.5
.5976/.2068= 2.88 so 3
.2068/.2068 = 1
.3923/.2068 = 1.89 so 2
now do i do it to all four with different denominators like
1.136/1.136= 1
.5976/1.136 =
and so on or do i do it by just that one
No, you're done, except for multiplying everything by 2 to get rid of the 1/2 in 5.5
So you have
H2O = 5.5 x 2 = 11
C2O4 = 3 x 2 = 6
Fe^+3= 1 x 2 = 2
K^+ = 4
So you have
K4Fe(C2O4)6*11H2O
I don't know what it is but something is wrong here BECAUSE Fe is NOT +3 in this formula, it is +4 and that's not possible. I don't know of ANY compound in which Fe is +4 and this one especially because it's listed in the problem as +3. The potassium ferrioxalate I know about is K3Fe(C2O4)3. Check your numbers in the orginal problemm Make sure your original post is correct.
Certainly! To calculate the number of moles and percent composition, you'll need to know the molar masses of each element or compound.
Let's take the example of calculating the moles and percent composition of H2O.
1. Calculate the moles of H2O:
The molar mass of water (H2O) can be found by adding the atomic masses of hydrogen and oxygen.
Molar mass of H2O = (2 * atomic mass of hydrogen) + atomic mass of oxygen
= (2 * 1.00784 g/mol) + 15.999 g/mol
= 18.015 g/mol
Moles of H2O = Mass of H2O (in grams) / Molar mass of H2O
Moles of H2O = 20.14 g / 18.015 g/mol
= 1.117 mol
2. Calculate the percent composition of H2O:
Percent composition is the mass fraction of an element or compound in a given sample. To calculate it, divide the mass of the element or compound by the total mass of the sample, and then multiply by 100.
Percent composition of H2O = (Mass of H2O / Total mass) * 100
Percent composition of H2O = (20.14 g / 98.18 g) * 100
≈ 20.51%
By following these steps, you can calculate the moles and percent composition for the other compounds as well. Repeat the same procedure using the molar masses for C2O4, Fe3+, and K+. You can find the atomic masses of the elements in the periodic table.
Hope this helps! Let me know if you have any further questions.