# calculus

If the nth partial sum of
an is sn=(3n-2)/(n+1)

what is an when x>1?
and what is the sum of an?

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1. I assume that Sn = sum(1..n) An, so Sn -> 3

Dunno where the x comes from, but if you mean when n > 1,

An = Sn - s(n-1)
= (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1)
= 5 / n(n+1)

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posted by Steve

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