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What is the pH of the solution created by combining 11.20 mL of the 0.10 M NaOH(aq) with 8.00 mL of the 0.10 M HCl(aq)?

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  1. NaOH + HCl ==> NaCl + HOH
    strong base + strong acid.
    Determine mols NaOH = M x L = ??
    Determine mols HCl = M x L = ??
    Determine which reactant is in excess, then calculate molarity NaOH or HCl and pH from that. Post your work if you get stuck.

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