Calculus HELP!!

6 2 6
Let u = 4 , v = 2 , w = 2
5 3 1

Show that 2u - 3v - w = 0. Use that fact to find x1 and x2 that satisfy the equation
6 2 6
4 2 {x1} = 2
5 3 {x2} 1

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asked by Sara

  1. Except that indeed 8 - 6 - 2 = 0
    I have no idea what you mean.
    Are x1 and x2 vectors multiplied by square matrices or what?

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    posted by Damon

  2. u=6
    4
    5

    v=2
    2
    3

    w=6
    2
    1

    show that 2u - 3v - w = 0

    Sorry!! I hope this makes a bit more sense...Can we try to do this step by step so I can understand it better?

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    posted by Sara

  3. Then after this, use that fact to find x1 and x2 that satisfies the equation:

    6 2 6
    4 2 2
    5 3 {x1 and x2} = 1

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    posted by Sara

  4. just add them up:
    2u-3v-w =
    12-6-6
    8-6-2
    10-9-1
    =
    0
    0
    0

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    posted by Steve

  6. The 6
    2
    1

    is supposed to be on the right hand side of the equal sign. I am so sorry again!!!

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    posted by Sara

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