# maths

A woman is now 4 times older than her daughter.Six years ago,the product of their ages was 136.Find their present ages.

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1. You can solve this easily as follows:
Let the woman age now = x
Daughter age now = y

First information says that
x = 4y
second information says that
(x-6)(y-6) =136
substitute from first into second
(4y-6)(y-6) = 136
4 y^2 - 30 y + 36 = 136
4 y^2 - 30y - 100 = 0
Simplfying
2 y^2 - 15y -50 =0
(2y+5)(y-10)=0
y = 10 as age can not be negative
Woman age = 4 * 10 = 40 years
Daughter age = 10 years

Good luck

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posted by Hussein
2. Thank you^^

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2. 👎 0
posted by mandy

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