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A woman is now 4 times older than her daughter.Six years ago,the product of their ages was 136.Find their present ages.

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asked by mandy
  1. You can solve this easily as follows:
    Let the woman age now = x
    Daughter age now = y

    First information says that
    x = 4y
    second information says that
    (x-6)(y-6) =136
    substitute from first into second
    (4y-6)(y-6) = 136
    4 y^2 - 30 y + 36 = 136
    4 y^2 - 30y - 100 = 0
    Simplfying
    2 y^2 - 15y -50 =0
    (2y+5)(y-10)=0
    y = 10 as age can not be negative
    Woman age = 4 * 10 = 40 years
    Daughter age = 10 years

    Good luck

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    posted by Hussein
  2. Thank you^^

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    posted by mandy

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