x^2-17x+52=0

But i don't know how to do..

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1. (x-4)(x-13)= 0
if you multiply the brackets you would go back to
x^2 - 17 x + 52=0

the best is to look for the solutionof quadratic functions on google where to get the roots of the equation you substitute in
x= -b +/- SQRT(b^2-4ac)/2a

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posted by Hussein

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