physics

using a powerful air gun, a steel ball is shot vertically upward with a velocity of 80 m/s, followed by another shot after 5 seconds. find the initial velocity of the second ball to meet the first ball 150 m from the ground.

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asked by Astro
  1. first ball:
    hf=vi1t-4.9t^2
    second ball
    hf=vi2(t-5)-4.9 (t-5)^2

    you know vi1, hf. You do not know t, vi2.

    in the first equation, solve for t.
    then, in the second equation, solve for vi2

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  2. THE ANSWER IS NEGATIVE VELOCITY WHAT THE PAK

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    posted by WEW

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