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Can someone please check my math Hw? Thank you!! Solve each system by elimination. 1. 8x+7y=1 9x7y=2 I got (1,1) 2. 4x+3y=1 4x7y=13 I got (2,2) 3. 7x6y=21 x6y=3 I got (3,0) 4. 2x+3y=16 2x5y=16 I got (8,0) 5.
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Solving ya Systems of Equations by elimination 14x+15y=3 21x20y=10 The LCM is 42 so I am able to get (14x +15y=15)3 = 42x+45=45 (21x20y=10)2 = 42x40y=20 y =7 but when I plug it in to try and figure out x I do not get a
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solve by elimination method 7x+15y=32 x3y=20
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use either substitution or elimination to solve 8x+15y=13 2x5y=1
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I need help! I am confused! Algebra solve using substitution or elimination.10x15y=10 4x+6y=0
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Solve by substitution or elimination method: 4x – 5y = 14 12x + 15y = 42 when i try this solution i end up cancelling out the whole problem. can someone please help me!
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solve the systems of equation: First : 4x2y = 2 Second: y = 4x7 Should i solve by using substitution, elimination or multiply then use elimination? Try adding them. Add up the left sides and the right sides (after rearranging
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We are learning how to solve systems using elimination. 2y  1 = 3x  y / 5 3x  4 / 8 = y/4 How would I begin to solve this? I'm mostly unsure of how to simplify the fractions. Thanks so much :)
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