# Calculus

Sketch the region and find its area.

S = {(x,y) | x > -6, 0 < y < e-x/2}

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1. area = ∫e^(-x/2) dx from x = -6 to ∞
= [-2 e^(-x/2) ] from -6 to ∞
= 0 - (-2e^3)
= 2e^3

note: as x ---> ∞ , e^(-huge) = 1/e^huge ---> 0

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posted by Reiny

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