# PreCAL

Write an equation in slope–intercept form of the line with the given parametric equations.
x = 9t + 2

y = –6t + 9
(A) y=-2/3x-3/7 (B) y=-3/2x+3/31
(C) y=31/3x-2/3 (D) y=-2/3x+31/3

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1. x = 9 t + 2

x - 2 = 9 t

( x - 2 ) / 9 = t

t = ( x - 2 ) / 9

y = – 6 t + 9

y = - 6 * ( x - 2 ) / 9 + 9

y = - 3 * 2 * ( x - 2 ) / ( 3 * 3 ) + 9

y = - ( 2 / 3 ) ( x - 2 ) + 9

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posted by Bosnian
2. x = 9t+2 --> t = (x-2)/9
y = -6t+9 --> t = (9-y)/6

then : (x-2)/9 = (9-y)/6

6x-12 = 81-9y
9y = -6x + 93
y = (-2/3)x + 31/3

looks like B)

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posted by Reiny
3. y = - ( 2 / 3 ) ( x - 2 ) + 9

y = - ( 2 / 3 ) x - ( 2 / 3 ) * ( - 2 ) + 9

y = - ( 2 / 3 ) x + 4 / 3 + 9

y = - ( 2 / 3 ) x + 4 / 3 + 27 / 3

y = - ( 2 / 3 ) x + 31 / 3

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posted by Bosnian
4. You are right Bosnian, it is D
Time to clean my glasses, lol

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posted by Reiny

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