PreCAL

Write an equation in slope–intercept form of the line with the given parametric equations.
x = 9t + 2

y = –6t + 9
Answer Choices
(A) y=-2/3x-3/7 (B) y=-3/2x+3/31
(C) y=31/3x-2/3 (D) y=-2/3x+31/3

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asked by PreCAL
  1. x = 9 t + 2

    x - 2 = 9 t

    ( x - 2 ) / 9 = t

    t = ( x - 2 ) / 9


    y = – 6 t + 9

    y = - 6 * ( x - 2 ) / 9 + 9

    y = - 3 * 2 * ( x - 2 ) / ( 3 * 3 ) + 9

    y = - ( 2 / 3 ) ( x - 2 ) + 9

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    posted by Bosnian
  2. x = 9t+2 --> t = (x-2)/9
    y = -6t+9 --> t = (9-y)/6

    then : (x-2)/9 = (9-y)/6

    6x-12 = 81-9y
    9y = -6x + 93
    y = (-2/3)x + 31/3

    looks like B)

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    posted by Reiny
  3. y = - ( 2 / 3 ) ( x - 2 ) + 9

    y = - ( 2 / 3 ) x - ( 2 / 3 ) * ( - 2 ) + 9

    y = - ( 2 / 3 ) x + 4 / 3 + 9

    y = - ( 2 / 3 ) x + 4 / 3 + 27 / 3

    y = - ( 2 / 3 ) x + 31 / 3


    Answer D

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    posted by Bosnian
  4. You are right Bosnian, it is D
    Time to clean my glasses, lol

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    posted by Reiny

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