trig

csc^4-cot^4= 1+cos^2/sin^2

i need help! please help me

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asked by jenny
  1. LS = (csc^2 Ø + cot^2 Ø)(csc^2 Ø - cot^2 Ø
    = (1 + cot^2 Ø + cot^2 Ø)(1+cot^2 Ø - cot^2 Ø
    = 1 + 2cot^2 Ø

    RS = (1 + cos^2 Ø)/sin^2 Ø
    = (sin^2 Ø + cos^2 Ø + cos^2 Ø)/sin^2 Ø
    = (sin^2 Ø + 2cos^2 Ø)/sin^2 Ø
    = 1 + 2 cot^2 Ø
    = LS

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    posted by Reiny
  2. forgot to mention that you cannot just skip the "angle" after a trig operator.
    What you typed would be like having an equation of the type ...

    √ = ∫ + ∑

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    posted by Reiny

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