# Algebra

1. (12g^4)^-1 (work check)

12g^-4 = 1/(12g^4)

2. (2y^4)^-3 (need help)

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3. 👁 99
1. #1 ok

#2 Hmmm. If you got 1, don't see why 2 is any problem

(2y^4)^-3 = 1/(2y^4)^3 = 1/(8y^12)

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posted by Steve
2. How did you get (8y^12)?

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3. (2y^4)^3 = (2)^3 * (y^4)^3 = 8 y^12

Just as (2*5)^2 = 2^2 * 5^2 = 4*25 = 100

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posted by Steve
4. Thanks, I get it now. One more...

(r^2 s)^5

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