science(chem)

Commercial hydrazine is sold as a 64% solution. Using that as your starting material, how would you prepare a 5% solution of hydrazine?

well if it is sold as 64% solution would that mean that it has 64g of hydrazine per 100ml of solvent(water)?
and what they want in the end is a 5% solution or 5g hydrazine per 100ml of water?

as for how to do this I'm not sure, mathematically or step wise either.

Thanks

1. 👍 0
2. 👎 0
3. 👁 110
1. percent weight/weight is, in this case,
64 g hydrazine in 100 g SOLUTION. IF, and only if, the density of that solution is 1.00 can that be 100 mL and then it is 100 mL solution and not 100 mL H2O. Since the density of hydrazine is 1.01, I suspect the density of the solution would be so close to 1 that it wouldn't matter; however, since you aren't give a density I assume you are to work the problem not using mL.
A 64% solution is [64 g N2H4/(64 g N2H4 + 36 g H2O)]*100 = 64%.
Now just change the numbers to what you want.
[64 g N2H4/(64 g N2H4 + y g H2O}]*100 = 5% and solve for y g H2O. Then y gH2O + 64 g = total grams of solution.
So you start with 100 g solution(64 g hydrazine) and dilute with water to 1280 g solution and you have a BUNCH of 5% solution. The problem makes it easier by not specifying how much solution is to be prepared. If you don't want that much just divide by an appropriate number to obtain a more manageable quantity. Check my thinking.

1. 👍 0
2. 👎 0
posted by DrBob222
2. I have to go out but I'll check and repost if I don't understand.

Thanks Dr.Bob

1. 👍 0
2. 👎 0
3. An ammonia solution is made by diluting 0.150L of the concentrated commercial reagent until the final volume reaches 1.00L.

1. 👍 0
2. 👎 0
posted by JED

Similar Questions

1. science(chem)

Commercial hydrazine is sold as a 64% solution. Using that as your starting material, how would you prepare a 5% solution of hydrazine? well if it is sold as 64% solution would that mean that it has 64g of hydrazine per 100ml of

asked by ~christina~ on May 5, 2008
2. Chemistry 2 - Acids and Bases

Hydrazine (NH2NH2) is a weak base that ionizes in water as follows. NH2NH2(aq) + H2O(l) HNH2NH2^+(aq) + OH^−(aq) Calculate the concentration of OH^− ions in a 0.20 M solution of hydrazine, given that the base-dissociation

asked by Jamie on February 28, 2018
3. Chemisty

Calculate the \rm pH of a 0.10 M solution of hydrazine, \rm N_2H_4. K_b for hydrazine is 1.3\times 10^{-6}.

asked by Karlie on June 14, 2013
4. Chemistry

The piperazine content of an impure commercial material can be determined by precipitating and weighing the diacetate: (C2H4)2N2H2 + 2 CH3COOH → (C2H4)2N2H2(CH3COOH)2 In one experiment, 0.3126 gram of the sample was dissolved in

asked by Tom on August 23, 2014
5. Chemistry

For the reaction of hydrazine (N2H4) in water, Kb is 3.0 10-6. H2NNH2(aq) + H2O(l) H2NNH3+(aq) + OH -(aq) Calculate the concentrations of all species and the pH of a 2.2 M solution of hydrazine in water. okay so i don't know how

asked by Lori on February 14, 2009
6. Chemistry (PLZ HELP)

Hydrazine, N2H4(aq), is used in the preparation of polymers, pharmaceuticals and rocket fuel. Hydrazine has alkaline properties similar to ammonia and will act as a weak base. Given that a 100 mL sample of 0.10 mol/L hydrazine

asked by Emily on May 23, 2018
7. Chemistry

Hydrazine, N2H4(aq), is used in the preparation of polymers, pharmaceuticals and rocket fuel. Hydrazine has alkaline properties similar to ammonia and will act as a weak base. Given that a 100 mL sample of 0.10 mol/L hydrazine

asked by Emily on May 23, 2018
8. Chemistry

For the reaction of hydrazine (N2H4) in water, Kb is 3.0 10-6. H2NNH2(aq) + H2O(l)--> H2NNH3+(aq) + OH-(aq) Calculate the concentrations of all species and the pH of a 1.6 M solution of hydrazine in water. [OH-] = [H2NNH3+] =

asked by Daniel on February 3, 2013
9. chemistry

A first-order reaction initially proceeds at a rate of 0.5 mol/ls. What will be the rate when half the starting material remains? When one-fourth of the starting material remains?

asked by Tri on July 6, 2008
10. math

the ratio of non-commercial to commercial veheicles is 14:5. If there are 108 more non-commercial, how many commercial and non-commercial

asked by Anonymous on September 12, 2018

More Similar Questions