physics

A net force of 100 newtons is applied to a 20 kg cart that is already moving at 3 meters per second. The final speed of the cart was 8 m/s. For how long was the force applied?

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asked by karen

  1. F=ma

    F=m(∆v/t)

    Solving for timt (t):

    t=(m∆v)/F

    Where

    t=?
    m=20.0kg
    ∆v=8m/s-3m/s=5m/s
    F=100N

    Solve for t:

    t=(20kg*5m/s)/100N

    t=1s

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    posted by Devron

  2. I assume that the force was applied exactly in the direction of motion

    change in momentum = 20(8-3)
    = 100 kg m/s

    Force = change in momentum /change in time
    which is another way of saying F = ma

    100 N = 100 kg m/s / change in time

    so change in time = 1 second

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    posted by Damon

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