# Algebra

How to solve d(d^-2)^-9? Please show and explain step-by-step.

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1. What do you have to solve exactly? Do you by chance mean simplify?

Should there be an equal sign in the expression that you typed?

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posted by Leo
2. Simplify, sorry. The answer says d^19, but I don't get how.

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3. d^1 * d^(-2*-9)

= d^1 * d^+18

= d^19

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posted by Damon
4. Thanks. Another one:

(z^8)^0 z^5

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5. ANYTHING AT ALL^0 = ONE
so
z^5

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posted by Damon

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