Physics

A tennis ball is thrown up with an initial speed of 22.5m/s. It is caught at the same distance above the ground.
A) how high does the ball rise
B) how long does the ball remain in the air?

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asked by Sandara

  1. initial KE=final PE
    1/2 m 22.5^2=m g h
    solve for h.

    time in air:
    hf=hi+vi*t-4.9t^2
    hf=hi and vi is given, solve for t.

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    posted by bobpursley

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