Find an equation for the line that passes through the point (2, -5) and is parallel to the x-axis and is parallel to the y-axis and is parallel to the line 2x - 4y = 3
the equation of a line parallel to the x-axis has the equation y = k. Since your line goes through (2,-5), you obviously want y = -5.
Similarly for the line parallel to the y-axis.
it has a slope of -3 the line that passes through the point (2, -5)
the line with slope of -3 through (2,-5) is
y+5 = -3(x-2)
Learn the various forms of equations for a line; it will come in handy many times in the future.
To find an equation for a line that passes through a given point and is parallel to a given line, we need to determine the slope of the given line. Then, we can use the point-slope form of a linear equation to find the equation of the parallel line.
First, let's find the slope of the given line 2x - 4y = 3. To do this, we need to rearrange the equation in slope-intercept form (y = mx + b), where m is the slope of the line:
2x - 4y = 3
-4y = -2x + 3
y = (1/2)x - 3/4
The slope of this line is 1/2.
Since the line we are looking for is parallel to the x-axis, its slope is zero. Therefore, the equation will have the form y = k, where k is a constant.
Since the line we are looking for is also parallel to the y-axis, its slope is undefined. Therefore, the equation will have the form x = k, where k is a constant.
Finally, let's use the given point (2, -5) to find the equation.
For a line parallel to the x-axis, the equation is y = k. Plugging in the given point (2, -5), we have -5 = k. Therefore, the equation of the line parallel to the x-axis passing through (2, -5) is y = -5.
For a line parallel to the y-axis, the equation is x = k. Plugging in the given point (2, -5), we have x = 2. Therefore, the equation of the line parallel to the y-axis passing through (2, -5) is x = 2.
So, there are two possible equations for the line that passes through the point (2, -5) and is parallel to the x-axis: y = -5 and x = 2.
Sorry I meant
Find an equation for the line that passes through the point (2, -5) and is parallel to the x-axis
Find an equation for the line that passes through the point (2, -5) and is parallel to the y-axis
Find an equation for the line that passes through the point (2, -5) and is parallel to the line 2x - 4y = 3
how can a single line be parallel to both perpendicular axes?
I'll assume you mean it's parallel to 2x-4y=3.
In that case, the slope is 1/2, so the line is
y+5 = 1/2 (x-2)