A bucket ofwater has weight of 40N.A man lifts the bucket by applying an upward force of 20N,At the sawe time a child pulls the bucket along with a horizontal force of 10N,Calculate the resultant force on the bucket
20N + 10N =R
400 + 100 = R
500 = R
R =22,36
To calculate the resultant force on the bucket, we need to consider both the vertical and horizontal components of the applied forces.
The vertical component includes the force exerted by the man, which is upward, and the weight of the bucket acting downward.
The horizontal component includes the force exerted by the child in the horizontal direction.
Let's break down the forces:
1. Vertical forces:
- The force exerted by the man: 20N (upward).
- The weight of the bucket: 40N (downward). Weight is a force acting vertically downward.
2. Horizontal force:
- The force exerted by the child: 10N (horizontal).
Now, let's calculate the resultant force:
1. Vertical component:
The net force acting in the vertical direction is the difference between the upward force exerted by the man and the weight of the bucket.
Resultant force in the vertical direction = Force by the man - Weight of the bucket
Resultant force in the vertical direction = 20N - 40N
Resultant force in the vertical direction = -20N (downward)
2. Horizontal component:
The resulting force in the horizontal direction is simply the force exerted by the child, as there are no other forces acting in that direction.
Resultant force in the horizontal direction = Force by the child
Resultant force in the horizontal direction = 10N
Therefore, the resultant force on the bucket is a combination of the vertical and horizontal components:
Resultant force = √(Resultant force in vertical direction)^2 + (Resultant force in horizontal direction)^2
Resultant force = √((-20N)^2 + (10N)^2)
Resultant force = √(400N^2 + 100N^2)
Resultant force ≈ √(500N^2)
Resultant force ≈ 22.4N
So, the resultant force on the bucket is approximately 22.4N.