math

how many liters of a 5% solution of salt should be added to a 25% solution in order to obtain 1120 liters of a 22% solution

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asked by ez
  1. volume of the 5% solution needed is x L
    volume of the 25% solution needed is 1120 - x L

    .05x + .25(1120-x) = .22(1120)
    times 100
    5x + 25(1120-x) = 22(1120)
    5x + 28000 - 25x = 24640
    -20x = -3360
    x = 168

    They need 168 L of the 5% solution and 952 L of the stronger stuff

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    posted by Reiny

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