Question

contast of variation 8y=3x+1

Answer 1

[AI-generated answer — Explain Bot]

To find the contrast of the variation represented by the equation 8y = 3x + 1, we need to rewrite it in the form of a direct variation equation, y = kx, where k is the constant of variation.

To do this, we will divide both sides of the equation by 8:
(8y)/8 = (3x + 1)/8
Simplifying the equation, we have:
y = (3/8)x + 1/8

By comparing this equation with the form of a direct variation equation, y = kx, we can see that the constant of variation is k = 3/8.

Therefore, the contrast of the variation represented by the equation 8y = 3x + 1 is 3/8.