Maths (Tangents and Normals)

find the points on the curve [(x^2 )+ (y^2) = 18] at which the tangents are parallel to the line x+y = 3

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asked by Sykox
  1. the line has slope -1

    x^2+y^2=18
    dy/dx = -x/y

    so, we need x = y

    x^2+x^2 = 18
    x = ±3, so the points are

    (-3,-3) and (3,3)

    visit wolframalpha.com and enter

    plot x^2+y^2=18, x+y = -6, x+y=6, x=3, y=3

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    posted by Steve

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