A solution is prepared by dissolving 3.44 g of sucrose, C12H22O11, in 118 g of water.

a) What is the molality of the resulting solution?

b) What is the mole fraction of water in this solution?

B)
moles of h2o=118g/18(g/mol)=6.5556 mol

moles of c12h22O11= 3.44g/342.3(g/mol)=0.10049 mol

--->6.5556 mol/(6.5556 mol + 0.10049 mol= 0.984902 mol

A)
M= (0.10049)/(0.00344 kg + 0.118 kg)= 0.82749 m c12h22O11

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3. 👁 108
1. 1st error: 3/300 = 0.01, not 0.10

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posted by Steve
2. how did you get that number?

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