Physics

Calculate the impulse (in kgm/s) received by a football when it's kicked in a kickoff. The ball has a mass of 0.27 kg and travels a horizontal distance of 68 m. The ball is kicked at an angle q of 20.5 with the horizontal and spends 2.276 seconds in the air.

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asked by Susan
  1. Help?

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    posted by Susan
  2. Vi is initial vertical velocity
    u is horizontal velocity
    S is initial speed

    Do vertical problem first knowing it spends 2.276 s in air

    That means it spends 1.138 seconds going up
    v = Vi - g t
    v = 0 at top
    0 = Vi - 9.81 (1.138)
    so
    Vi = 11.16 meters/second

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    posted by Damon
  3. Is that enough?
    remember tan 20.5 = Vi/u

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    posted by Damon
  4. so u = 29.8 meters/s
    which you could also get from u = 68/2.276

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    posted by Damon
  5. S, initial speed = sqrt(u^2+v^2)

    impulse = initial momentum
    = .27 S

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    posted by Damon
  6. d = Xo*T = 68 m.
    Xo * 2.276 = 68
    Xo = 29.9 m/s. = Hor. component of
    initial velocity.

    Vo = Xo/cosA = 29.9/cos20.5 = 31.9 m/s =
    Initial velocity.

    Impulse = m*Vo = 0.27 * 31.9 = 8.61
    kg.m/s.

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    posted by Henry

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