A choir is singing at a festival. On the first night 12 choir members were absent,so the choir stood in 5 equal rows. On the second night only one member was absent, so they stood in 6 equal rows. the same number of people stood in each row each night. How many members are in the choir?
I hope this helps!
37-12=25 5 rows of 5
37-1=36 6 rows of 6
from the first data:
it has to be a multiple of 5 + 12, could be
17 22 27 32 37 42 47 ...
from the 2nd data:
it has to be a multiple of 6 + 1 , could be
7 13 19 25 31 37 43 ..
ahhh, 37 is found in both , which is also Lila's answer.
There were 37 choir members
THIS DOESNT HELP
To find the total number of choir members, we can use algebraic reasoning by setting up two equations based on the given information.
Let's assume the total number of choir members is "x".
On the first night, with 12 members absent, the choir stood in 5 equal rows. So, each row had (x-12)/5 members.
On the second night, with 1 member absent, the choir stood in 6 equal rows. So, each row had (x-1)/6 members.
Now, we can set up the following equations based on the given information:
1. (x-12)/5 = (x-1)/6 (equation for the number of members in each row on the first night and the second night)
2. (x-12)/5 = (x-1)/6
To solve this equation, we can cross-multiply:
6(x-12) = 5(x-1)
6x - 72 = 5x - 5
Now, let's solve for x:
6x - 5x = -5 + 72
x = 67
Therefore, there are 67 members in the choir.