# Chemistry Damon step bystep for me

A 0.887g sample of a mixture of nacl and kcl is dissolved in water and the solution is treated with an excess of agn03 producing 1.822g of agcl. What is the percent by mas of each compound in the mixture
My calculation 1.822g/143g/mol = 0.013M
x/58 + y/74 (0.887g-x) = 0.013M
I want you to explain clearly step by step for me. Please Damon for me.

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1. Let X = g NaCl
and Y = g KCl
---------------
You need two equations.
g NaCl + g KCl = 0.887 is #1.
g AgCl from NaCl + g AgCl from KCl = 1.822 is #2.

For #1 you have X + Y = 0.887
For #2 you have
X(MMAgCl/MMNaCl) + Y(MMAgCl/MMKCl) = 1.822 where MM stands for molar mass.
Solve the two equations for X and Y, then
%NaCl = (mass NaCl/0.887)*100 and
%KCl = (mass KCl/0.887)*100

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