Calculus

Find the position s as a function of time t from the given velocity v=ds/dv. Then evaluate the constant of integration so that s = s0 when, t = 0. 1. v = 3t2 , s0 = 4 I don't quite understand what the question is asking or what is s0 mean. Than

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asked by Shadow
  1. v = ds/dt or v = ds/dv ?? Please do not confuse me.

    if ds/dt = v = 3 t^2
    then
    s = t^3 + c
    when t = 0, s = s0 = 4 so constant of integration c = 4

    s = t^3 + 4

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    posted by Damon

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