# PHYSICS(HELP)

A small block of mass m=1 kg glides down (without friction) a circular track of radius R=2 m, starting from rest at height R. At the bottom of the track it hits a massless relaxed spring with spring constant k= 11 N/m, which starts to be compressed as the block continues to move horizontally. Note that we assume no energy loss during this “collision". There is friction between the block and the horizontal surface, and it is not uniform. As a function of distance, the friction coefficient varies like μ(x)=αx, with α= 1.0 m−1. Assume for simplicity that static and dynamic friction coefficients are the same, and use g=10 m/s2. (See figure)

(a) What is the maximal distance x1 that the block moves horizontally away from the track at x=0? (in meters)

x1=

(b) What time t1 does it take for the block to travel between x=0 (relaxed spring) and x=x1 (block at first stop)? (in seconds)

t1=

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3. 👁 190
1. x_1=sqrt(2gRm/(mg*alpha+k))

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2. When does this exam finally end?

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posted by Damon
3. when some one tells us what t_1 is

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posted by fighter
5. this exam ends tommorow at midnight

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6. how to find alpha?

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posted by asd
7. alpha is 1.5 m^-1

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posted by Hawk
8. how can we find t???

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posted by Hawk
9. SOMEONE PLEASE TELL THE FORMULA FOR t_1

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posted by fighter
10. t_1 = pi / (2*w) where w = sqrt((k+alpha*m*g)/m)

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11. how did you find alpha?

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posted by Greco
12. Greco, alpha is 1.5 m^-1
or I am wrong???

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posted by Hawk
13. "ì(x)=áx, with á= 1.0 m−1" so alpha is 1.0 m^-1

i got a green tick so in this problem alpha is 1.0 m^-1. In mine was
m g k R a 1 10 8 2 0.8

x1=1.58
t1=0.59

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posted by Greco

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