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Calculus
Note that pi lim arctan(x ) =  x > +oo 2 Now evaluate / pi \ lim arctan(x )   x x > +oo \ 2 / I'm not exactly sure how to attempt it. I have tried h'opital's rule but I don't believe you can use it here. Any help
asked by Frederique on November 19, 2006 
Math
Arrange these in order from least to greatest: arctan(sqrt3), arctan 0, arctan(1/2) So far I got the first two values, arctan(sqrt3), and that's 150 degrees. Arctan 0 would be zero degrees. I'll use just one answer for now, but
asked by Anonymous on August 13, 2009 
precal
The values of x that are solutions to the equation cos^(2)x=sin2x in the interval [0, pi] are a. arctan(1/2) only b. arctan(1/2) and pi c. arctan(1/2) and 0 d. arctan(1/2) and (pi/2) e. arctan(1/2), o, and (pi/2)
asked by Carson on March 25, 2013 
solving trigonometrical equations
arctan(tan(2pi/3) thanks. arctan(tan(2pi/3) = pi/3 since arctan and tan are inverse operations, the solution would be 2pi/3 the number of solutions to arctan(x) is infinite, look at its graph. generally, unless a general solution
asked by Jen on April 10, 2007 
calc
also: integral of tan^(1)y dy how is integration of parts used in that? You write: arctan(y)dy = d[y arctan(y)]  y d[arctan(y)] Here we again have used the product rule: d(fg) = f dg + g df You then use that: d[arctan(y)] =
asked by marsha on May 23, 2007 
limiting position of the particle
A particle moves along the x axis so that its position at any time t>= 0 is given by x = arctan t What is the limiting position of the particle as t approaches infinity? Answer is pi/2 How do I solve this? Thanks a lot. You want
asked by Jen on October 20, 2006 
calculus
Now we prove Machin's formula using the tangent addition formula: tan(A+B)= tanA+tanB/1tanAtanB. If A= arctan(120/119) and B= arctan(1/239), how do you show that arctan(120/119)arctan(1/239)=arctan1?
asked by alex on May 23, 2010 
Calculus prince@18
let the function h(x)= (integrand symbol from 2 to x^2)arctan (t) dt. Find h'(x). This question confused me because i know the derivative of an integral is the original function. I just need help with finding the derivative of
asked by Prince@18 on February 9, 2017 
calculus
h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? > using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2) Part 2: By the chain
asked by Anonymous on July 14, 2011 
calculus
h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? > using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2) Part 2: By the chain
asked by Anonymous on July 14, 2011