science please check my answer

A boy climbs to the roof of his house and drops a 0.40 kg rubber ball from the 7.5-meter peak of the house.

How much energy was lost in the process?

So I got 48 J is this correct?

The bounce takes place over a 170 ms time interval. What is the impulse given to the ball during this time?

74 is this right?

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  3. 👁 74
asked by Katie
  1. Well. I do not know how much was lost in that first bounce. The answer is all of it after all bouncing has ended.
    All of it is m g h =.4 * 9.81 * 7.5=
    29.43 Joules

    Now I will have to assume that the ball bounced not at all or perfectly. I guess I will assume that it bounced perfectly.
    How fast was it going?
    (1/2) m v^2 = 29.43 Joules
    v = 12.1 m/s down speed
    If the bounce is perfect, 12.1 up as well
    change in momentum = impulse =
    .4 (12.1)(2) = 9.7

    The next part of the question is probably what is the average force
    F = change in momentum/change in time = impulse/time = 9.7/(.170)

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    posted by Damon
  2. I got 57. 06 N, is that correct?

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    posted by Katie
  3. How do I find the average acceleration of the ball?

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    posted by Katie
  4. 9.7/.170 = 57.06 Newtons, yes

    F = m a

    57.06 = .4 a

    a = 143 m/s^2

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    posted by Damon

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