express 20sin theta + 4 cos theta as R sin(theta + alpha) R sin(theta + alpha) = R cos(alpha)sin(theta) + R sin(alpha)cos(theta) ----> Rcos(alpha) = 20 Rsin(alpha) = 4 The x-y coordinates of a point on a circle of radius R that
when solving for all solutions how do I work out this problem: cos4(alpha)=cos2(alpha) and when verifying each identity how do I complete this problem: sin (alpha/2)=sec alpha -1/2sin (alpha/2)sec alpha
evaluate the following in exact form, where the angeles alpha and beta satisfy the conditions: sin alpha=4/5 for pi/2 < alpha < pi tan beta=7/24 for pie < beta < 3pi/2 answer choices A. sin(beta+alpha) B.
assume A= alpha using complementary rule how do I solve for alpha? cos(2A+40) =sin(3A-60) I don't understand how to start the question. What are the steps in solving for alpha. Do i get cos to equal sin somehow?