# Dont get this question..

what are the zeros of the function?
y=(x-3)(x+2)(x-2)

a.-3,2,-2
b.-3,2,2
c.3,-2,2
d.3,2,2

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1. zeros of a function are those values of x which make y = 0
that is, where does the graph cross or touch the x-axis

The ideal expression has the function in factored form, we have that already, so it is easy
Just set each of the factors equal to zero and solve

e.g. x-3 = 0
x = 3
etc for the other two.

After doing a few, you should be able to do this in your head.
For this one, the zeros are 3, -2, +2

Wolfram shows this nicely
http://www.wolframalpha.com/input/?i=plot++y%3D%28x-3%29%28x%2B2%29%28x-2%29

notice for what values of x the graph crosses the x-axis.

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posted by Reiny

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