algebra 1

parallel and perpendicular lines
write the slope-intercept for an equation of the line that passes through the given point and is perpendicular to the graph of each equation (4-2) y=1/2 +1, ( 2,-3) y= -2/3+4 (-8,-7) y=-x-8 (6,-2) y=-3x-6

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  1. I will do the last one, you do the others the same way

    point is (6,-2)
    line is y = -3x - 6

    slopes of perpendicular lines are negative reciprocals of each other.

    So the new line is
    y =(1/3)x + b
    sub in the given point
    -2 = (1/3)(6) + b
    -2 = 2 + b
    -4 = b

    new equation: y = (1/3)x - 4

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    posted by Reiny

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