You can add or subtract complex numbers by treating the i as a variable and combining like terms.
I am having a lot of trouble figuring out these equations with imaginary numbers.
1. (3+2i)+(7-i)=
2.(1-6i)+(2-i)=
3. (2+i)-(3+i)=
4.(4+i)-(2-i)=
Can someone please walk me through how to do these problems? Thanks.
(3+2i)+(7-i)=
3 + 2i + 7-i=
3 + 7 + 2i - i =
10 + i
To solve these equations with imaginary numbers, you can follow these steps:
1. Combine real terms together and complex terms together.
2. Add or subtract the real parts separately and the imaginary parts separately.
3. Write your answer in the form a + bi, where a is the real part and b is the imaginary part.
Let's go through the first problem step by step:
(3+2i) + (7-i) =
Combine the real terms (3 and 7) and the imaginary terms (2i and -i):
3 + 7 + 2i - i =
Combine the real terms (3 and 7) to get 10:
10 + 2i - i =
Combine the imaginary terms (2i and -i) to get i:
10 + i
So, the answer to the first problem is 10 + i.
You can follow the same steps to solve the other problems.