posted by AROWOLO TEMITOPE
A is a solution of trioxonitate acid of an unknown concentration, B is a standard solution of sodium hydroxide containing 4.00g per dm3 of solution 25cm3 portion of solution B require an average of 24cm3 of solution A for complete neutralization. Write a balance equation for the reaction.calculate
A. Concentration of B in grame per dm3
B. Concentration of A in grame per dm3
C. Concentration in grame per dm3 of the trioxonitrate(v) acid in solution A
The correct name for trioxonitrate(v) acie is nitric acid or HNO3.
HNO3 + NaOH ==> NaNO3 + H2O
(B) = 4.00 g/dm3
M = molarity B = 4.00/molar mass NaOH = ?
M HNO3 x mL HNO3 = M NaOH x mL NaOH. You know M HNO3, mL HNO3 and M NaOH. Solve for M HNO3 in mols/dm3 and convert to grams/dm3.
C is the same question as B.
Post your work if you get stuck.