How many moles of Cu2+ ions are present in 1L of .125M CuSO4:5H2O solution?
mols CuSO4.5H2O = M x L = ?
There is 1 mol Cu^2+ in 1 mol CuSO4.5H2O so ........
To determine the number of moles of Cu2+ ions present in 1L of 0.125M CuSO4:5H2O solution, we first need to find the molar mass of CuSO4:5H2O.
The molar mass of CuSO4:5H2O can be calculated as follows:
Molar mass of Cu = 63.55 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of O (4 atoms) = 16.00 g/mol x 4 = 64.00 g/mol
Molar mass of H (10 atoms) = 1.01 g/mol x 10 = 10.10 g/mol
Molar mass of CuSO4:5H2O = (63.55 g/mol) + (32.07 g/mol) + (64.00 g/mol) + (10.10 g/mol) = 169.72 g/mol
Now, we can calculate the moles of Cu2+ ions using the molarity and volume of the solution:
Moles of Cu2+ ions = Molarity * Volume
= 0.125 mol/L * 1 L
= 0.125 mol
Therefore, there are 0.125 moles of Cu2+ ions present in 1L of 0.125M CuSO4:5H2O solution.
To determine the number of moles of Cu2+ ions present in 1L of a .125M CuSO4:5H2O solution, we need to use the molarity (M) and the stoichiometry of the compound.
The molarity formula is: Molarity (M) = moles of solute / volume of solution (in liters)
In this case, the molarity (M) is given as .125M, and the volume of the solution is 1L.
To find the moles of solute (Cu2+ ions), we first need to determine the molar mass of CuSO4:5H2O.
- The molar mass of CuSO4 is: 63.546 g/mol (for Cu) + 32.07 g/mol (for S) + 4 * 16.00 g/mol (for O)
= 159.609 g/mol
- The molar mass of H2O is: 2 * 1.008 g/mol (for H) + 16.00 g/mol (for O)
= 18.015 g/mol
- Since there are 5 water molecules (H2O) in CuSO4:5H2O, the total molar mass is: 159.609 g/mol + 5 * 18.015 g/mol
= 249.685 g/mol
Now we can calculate the number of moles (n) of Cu2+ ions using the molarity expression:
n = M * V (moles of solute) = Molarity * volume (in liters)
n = 0.125 mol/L * 1 L = 0.125 moles
However, we need to account for the stoichiometry. In CuSO4, there is one Cu2+ ion per formula unit. Therefore, the number of moles of Cu2+ ions is also equal to 0.125 moles.
Therefore, there are 0.125 moles of Cu2+ ions present in 1L of a 0.125M CuSO4:5H2O solution.