Trig
posted by Meranda
An airplane flies 180 miles from point A in the direction 120 degrees and then travels 210 degrees for 80 miles. Approximately how far is the airplane from point A?
I know that I will need to use the law of cosine. distance^2= a^2+b^22abcos?
I am not sure how to find the angle
An explanation of how to draw the triangle would be great!

scott
you could resolve the two legs into northsouth and eastwest components, and add them

Meranda
Like an x and yaxis?

Meranda
Would the angle between the two sides be 150 degrees? If not, then I need more explanation.

Henry
Disp. = 180mi[120o] + 80mi[210o].
X = 180*sin120 + 80*sin210 = 115.9 Mi.
Y = 180*Cos120 + 80*Cos210 = 159.3 Mi.
Disp. = Sqrt(X^2+Y^2). 
Meranda
We haven't learned about dispositions yet so I don't think that's how I am supposed to solve it

Meranda
Anybody else that can help me with this?

Henry
Disp. = Displacement which is the straight line distance from the starting point (A) to the
destination. I used vector analysis and trig to solve it. The only remaining method is
The Law of Sine and Cosines.
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