A 10 cm long, 2cm wide wooden wedge is pushed into a soft wood block.calculate: a) the velocity ratio of the wedge b) the load on the soft wood if the effort applied is 30N
Tricky
If it goes in 10 cm, the wood on the left is pushed 1 cm and the wood on the right is pushed 1 cm.
Therefore I would say the velocity of the wood on each side of the wedge was 1/10 times the velocity of the wedge.
30 * 10 = 300 Newtons
thanks
VR=L×T
10cm=0.1m
2cm=0.02
0.02×0.1
0.002
To calculate the velocity ratio of the wooden wedge and the load on the soft wood when an effort of 30N is applied, we need to understand the basic principles of wedges and simple machines.
A wedge is a simple machine that consists of a thick end and a thin end. It is commonly used to split or separate objects by applying an inward force. The velocity ratio of a wedge is determined by the ratio of its length to its width.
In this case, the wooden wedge has a length of 10 cm (or 0.1 meters) and a width of 2 cm (or 0.02 meters).
a) To calculate the velocity ratio of the wedge, we divide the length of the wedge by its width:
Velocity Ratio = Length of Wedge / Width of Wedge
Velocity Ratio = 0.1 meters / 0.02 meters
Velocity Ratio = 5
Therefore, the velocity ratio of the wooden wedge is 5.
b) To calculate the load on the soft wood when an effort of 30N is applied, we can use the formula for calculating mechanical advantage:
Mechanical Advantage = Load / Effort
In this case, the effort applied is given as 30N. Since the load is unknown, we need to rearrange the formula to solve for the load:
Load = Mechanical Advantage * Effort
We already calculated the velocity ratio as 5, which is also the mechanical advantage. Substituting the values into the formula:
Load = 5 * 30N
Load = 150N
Therefore, the load on the soft wood when an effort of 30N is applied is 150N.