Owen and Ethan have $175 together. How much money does each of them have if Ethan has $33 more than Owen?
thx
x + x + 33 = 175
Solve for x.
Figure out how much each has.
To solve this problem, let's use algebraic expressions.
Let's assume Owen has x dollars. Since Ethan has $33 more than Owen, Ethan would have x + $33.
We are given that Owen and Ethan have $175 together, so we can write the equation:
x + (x + $33) = $175
Now, let's simplify the equation:
2x + $33 = $175
To solve for x, we isolate the variable:
2x = $175 - $33
2x = $142
To find the value of x (Owen's money), we divide both sides of the equation by 2:
x = $142 / 2
x = $71
Therefore, Owen has $71.
To find Ethan's money, we substitute the value of x into the equation x + $33:
Ethan's money = $71 + $33
Ethan's money = $104
Therefore, Ethan has $104.
x+x+33=175
x + x=175-33
the 33 became -33 because it crossed over the =sign
at the back of any variable that seems to have no number is 1
1x +1x =2x
175-33=142
2x=142
but because we are looking for x not 2x we have to get rid of the coefficient which is 2 we divide both sides by 2
2x/2=142/2
x=71
so each of them have $71
to check if it is correct we do
$71+$71+$33=$175
so therefore it is correct.