The index of refraction of diamond is 2.42. What would be the speed of a light wave passing through a this medium?
8.1 x 10 ^-9 m/s
1.2 x 10^8 m/s
7.3 x 10^8 m/s
9 x 10^-9 m/s
To find the speed of light wave passing through a medium with a given index of refraction, you can use the equation:
Speed of light in vacuum / Index of refraction = Speed of light in the medium
The speed of light in vacuum is a constant value, which is approximately 3 x 10^8 m/s.
So, using the equation:
Speed of light in vacuum / Index of refraction = Speed of light in the medium
Speed of light in vacuum / 2.42 = Speed of light in the medium
Speed of light in the medium = 3 x 10^8 m/s / 2.42
Calculating the result:
Speed of light in the medium ≈ 1.24 x 10^8 m/s
Therefore, the correct answer is 1.2 x 10^8 m/s.
3*10^8/2.42
http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/refr.html
Hey, do you not have a text?