Implants carbon dioxide combined with water and energy to form glucose and oxygen gas. Right off the balance equation for this reaction. Glucose =C6H12O6.
Given 78g of water. How many grams of glucose can be formed?
6CO2 + 6H2O ==> C6H12O6 + 6O2
mols H2O = grams/molar mass = ?
Convert mols H2O to mols Glucose. That is mols H2O x 1 mol glucose for 6 moles H2O
Then grams glucose = mols glucose x molar mass glucose.
Post your work if you get stuck.
To answer this question, we need to balance the equation for the reaction between carbon dioxide (CO2) and water (H2O) to form glucose (C6H12O6) and oxygen (O2) gas.
The balanced equation is as follows:
6 CO2 + 12 H2O → C6H12O6 + 6 O2
From the balanced equation, we can see that for every 6 moles of carbon dioxide (CO2) and 12 moles of water (H2O), we obtain 1 mole of glucose (C6H12O6).
Given that we have 78 grams of water (H2O), we need to convert this to moles to determine the amount of glucose that can be formed.
The molar mass of water (H2O) is:
2(1.008 g/mol) + 16.00 g/mol = 18.02 g/mol (rounded to two decimal places)
Using this molar mass, we can calculate the number of moles of water:
78 g / 18.02 g/mol = 4.33 moles of water (rounded to two decimal places)
Since the balanced equation shows that we need 12 moles of water to produce 1 mole of glucose, we can set up a ratio to determine the amount of glucose formed.
4.33 moles of water × (1 mole of glucose / 12 moles of water) = 0.36 moles of glucose (rounded to two decimal places)
Finally, to find the mass of glucose formed, we can multiply the number of moles of glucose by its molar mass:
0.36 moles of glucose × 180.16 g/mol (molar mass of glucose) ≈ 65.25 grams of glucose
Therefore, approximately 65.25 grams of glucose can be formed from 78 grams of water.