Mr Lin gave a total of 3600 to his wife and two children. His wife received 500 more than first childvand the second child received half as much as first child. How much did first child receive
(x+500) + x + (x/2) = 3600
Now just find x
Let's assume the amount received by the first child as "X".
According to the given information:
- The wife received 500 more than the first child, so the wife received "X + 500".
- The second child received half as much as the first child, so the second child received "X/2".
The total amount given to the wife and two children is 3600:
X + (X + 500) + (X/2) = 3600.
We can simplify the equation:
2X + 500 + X/2 = 3600.
To remove the fraction, we can multiply every term by 2:
4X + 1000 + X = 7200.
Combining like terms:
5X + 1000 = 7200.
Subtracting 1000 from both sides:
5X = 6200.
Dividing both sides by 5:
X = 1240.
Therefore, the first child received 1240.
To find out how much the first child received, we need to solve the problem step by step.
Let's assume the amount the first child received is x.
According to the problem, Mr. Lin's wife received 500 more than the first child. Hence, the amount his wife received is x + 500.
The problem also states that the second child received half as much as the first child. So, the amount the second child received is x/2.
The total amount given is the sum of the amounts given to each person, which is given to be 3600.
Therefore, we can set up the equation: x + (x + 500) + (x/2) = 3600.
To solve this equation, let's simplify it:
Combining like terms, we get: (2x + 1000) + x/2 = 3600.
Multiplying the entire equation by 2 to get rid of the fraction, we have: 4x + 2000 + x = 7200.
Combining like terms again, we get: 5x + 2000 = 7200.
Subtracting 2000 from both sides, we have: 5x = 5200.
Dividing both sides by 5 to isolate x, we find: x = 1040.
Therefore, the first child received 1040.