Each car in a rental fleet is either red or white, and there are 75 cars total. There are three more white than twice the number of red cars. How many cars are white?
A) 24
B) 47
C) 48
D) 51
How do I solve this?
W = 2R + 3
R + W = 75
Substitute 2R+3 for W in the second equation and solve for R. Insert that value into the first equation to solve for W.
But I’m in 2nd I’m not sure
To solve this problem, you can set up a system of equations based on the given information.
Let's assume that the number of red cars is represented by the variable "r" and the number of white cars is represented by the variable "w".
We can write two equations based on the information given:
1. There are 75 cars total: r + w = 75
2. There are three more white cars than twice the number of red cars: w = 2r + 3
Now, we can solve this system of equations to find the value of "w" (the number of white cars).
One way to solve this system is by substitution. We can rearrange equation 2 to solve for "r":
w = 2r + 3
By rearranging this equation, we get:
r = (w - 3) / 2
We can substitute this value of "r" into equation 1:
(r) + w = 75
((w - 3) / 2) + w = 75
(w - 3) + 2w = 150
3w - 3 = 150
3w = 153
w = 51
Therefore, the number of white cars is 51. So the answer is option D) 51.
Given that rectangle MNOP rectangle STUV, what is the length of TU?
First, do your own post rather than adding on to another.
Second, you have insufficient data.