In a software company 30% workers are BTeach holders 25%are m.ba and 20% hold both these degrees. If 325 workers are without any professional degree how many workers are there in the company in all.
30% + 25% + 20% = 75% hold degrees; therefore, 100%- 75% = 25% that do not
x = number of workers
0.25x = 325. Solve for x.
I disagree ..
number(BT or MBA) = 30%+25% - 20% = 35%
(we can't count the 20% twice )
so 65% are without degrees
.65x= 325
x = 500
I worried about counting them twice, also; however, I finally decided we had four separate and distinct groups. One pool of 30% had BT, one pool of 25% had MBA, a third pool of 20% had both (this is a separate group that I didn't overlap with the other three), which left a fourth pool of 25% with no degrees. My interpretation may not be right but that's my rationale. By having four pools I was trying to avoid counting them twice.
In these kind of questions, when they state that 30% workers are BTeach holders, we don't assume that it is 30% exclusively.
e.g. When I say, that 8% of boys play football, that doesn't mean that they can't play some other sport as well.
In a Venn diagram for this question, I would draw two intersecting circles, label the intersection 20%, the "only BT" circle as 30-20 or 10% , and the "only MBA" section as 25-20 or 5%.
So that would add up to (20+10+5)% or 35% leaving 65% without those two degrees.
then .65x = 325
etc
I agree with your interpretation.
To find the total number of workers in the company, we need to subtract the number of workers without any professional degree from the total workforce.
Given that 30% of workers have a BTeach degree, we can calculate the number of workers with a BTeach degree by multiplying 30% by the total number of workers. Similarly, we can calculate the number of workers with an MBA degree by multiplying 25% by the total number of workers.
Next, we need to account for the fact that 20% of workers hold both degrees. So, we need to subtract this percentage from the total number of workers with both degrees.
Let's assume the total number of workers in the company is X.
Number of workers with a BTeach degree = 30% of X = (30/100)X
Number of workers with an MBA degree = 25% of X = (25/100)X
Number of workers with both degrees = 20% of X = (20/100)X
Now, the number of workers without any professional degree is given as 325.
So, we can express this information in an equation as:
Number of workers with a BTeach degree + Number of workers with an MBA degree - Number of workers with both degrees = Number of workers without any professional degree
((30/100)X) + ((25/100)X) - ((20/100)X) = 325
To solve this equation, we can simplify it by multiplying through by 100 to get rid of the percentages:
30X + 25X - 20X = 32500
35X = 32500
X = 32500 / 35
X ≈ 928.57
Since we cannot have a fraction of a worker in the company, we can round this up to the nearest whole number.
Therefore, there are approximately 929 workers in the company in total.