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posted by Sakthieswary .
The roots of the equation x^2+(a+3)x2b=0 are 2 and 3.Find the values of a and b.

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Damon
(x+2)(x+3) =x^2 + 5 x + 6
so
(a+3) = 5
2b =6
a = 2
b = 3
check
x^2 + 5 x + 6 = 0
(x+2)(x+3)=0
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